1. 12 members were present at a board meeting. Each member shake hands with all of the other members before and after the meeting .How many hand shakes were there?
a) 130
b)134
c)132
d)135
Answer: C
Explanation:
In order to have a hand shake there must be two members. Therefore to select 2 out of 12 we have 12C2.
This happens twice that is before and after the meeting
Answer = 12C2 ×2 = 132
a) 130
b)134
c)132
d)135
Answer: C
Explanation:
In order to have a hand shake there must be two members. Therefore to select 2 out of 12 we have 12C2.
This happens twice that is before and after the meeting
Answer = 12C2 ×2 = 132
2. An emergency vehicle travels 10 miles at a speed of 50 miles per hour. How fast must the vehicle travel on return trip if the round trip travel time is to be 20 minutes?
a) 75 mph
b) 70 mph
c) 65 mph
d) 80 mph
Answer: a
Explanation:
Going trip time = t = ds = 1050×60 = 12 minutes.
Given total time = 20 minutes
Return trip time = Total time – Going trip time = 20 – 12 = 8 minutes = 860 hours.
As the distance is 10 miles during even return trip,
The return speed = dt = 10860 = 10×608 = 75 mph
a) 75 mph
b) 70 mph
c) 65 mph
d) 80 mph
Answer: a
Explanation:
Going trip time = t = ds = 1050×60 = 12 minutes.
Given total time = 20 minutes
Return trip time = Total time – Going trip time = 20 – 12 = 8 minutes = 860 hours.
As the distance is 10 miles during even return trip,
The return speed = dt = 10860 = 10×608 = 75 mph
3. Mary and John can do a piece of work in 24 day; John and Vino in 30 days;Vino and Mary in 40 days. If Mary, John and Vino work together they will complete work in ?
a) 10 days
b) 20 days
c) 47 days
d) 45 days
Answer: b
Explanation:
Given that
Mary and John take 24 days; i.e., (Mary + John)’s 1 day’s work = 124
John and Vino take 30 days; i.e., (John + Vino)’s 1 day’s work = 130
Vino and Mary take 40 days; i.e., (Vino + Mary)’s 1 day’s work = 140
Adding above 3 equations, we get,
[(Mary + John) + (John + Vino) + (John + Vino)]’s 1 day’s work = 124+130+140
2((Mary + John + Vino)’s 1 days work = 124+130+140
2(Mary + John + Vino)’s 1 days work = 5+4+3120 = 110
Therefore, (Mary + John + Vino)’s 1 days work = 120
i.e., Mary, John and Vino together can complete the work in 20 days.
a) 10 days
b) 20 days
c) 47 days
d) 45 days
Answer: b
Explanation:
Given that
Mary and John take 24 days; i.e., (Mary + John)’s 1 day’s work = 124
John and Vino take 30 days; i.e., (John + Vino)’s 1 day’s work = 130
Vino and Mary take 40 days; i.e., (Vino + Mary)’s 1 day’s work = 140
Adding above 3 equations, we get,
[(Mary + John) + (John + Vino) + (John + Vino)]’s 1 day’s work = 124+130+140
2((Mary + John + Vino)’s 1 days work = 124+130+140
2(Mary + John + Vino)’s 1 days work = 5+4+3120 = 110
Therefore, (Mary + John + Vino)’s 1 days work = 120
i.e., Mary, John and Vino together can complete the work in 20 days.
4. My friend collects antique stamps. she purchased two, but found that she needed to raise money urgently. So she sold them for Rs. 800 each. On one she made 20% and on the other she lost 20%. How much did she gain or lose in the entire transaction?
a) she lost Rs 500.67
b) she lost Rs 666.67
c) she gain Rs 666.67
d) she gain Rs 500.67
Answer: b
Explanation:
Selling prices were given. Assume that on the first stamp she made profit and on the second stamp she made loss.
So cost prices of the both stamps = 800120%+80080% = 1666.66
So She incurred a loss of 66.66 rupees.
a) she lost Rs 500.67
b) she lost Rs 666.67
c) she gain Rs 666.67
d) she gain Rs 500.67
Answer: b
Explanation:
Selling prices were given. Assume that on the first stamp she made profit and on the second stamp she made loss.
So cost prices of the both stamps = 800120%+80080% = 1666.66
So She incurred a loss of 66.66 rupees.
5. If the sum of n terms of two series in A.P. are in the ratio (5n + 4) : (9n + 6) then find the ratio of their 13th terms.
a. 129231
b. 12
c. 2315
d. None of the above
Answer: a
Explanation:
Formula for sum of n terms in AP = Sn = n2(2a + (n – 1)d ]
5n + 4 ? 5(n – 1) + 9 ? [2(92)+(n?1)5]
Common difference (d) = 5, First term (a) = 92
Similarly
Second series given 9n + 6 ? 9(n – 1) + 15 ? [2(152)+(n?1)9]
Common difference (d) = 9, First term (a) = 152
So
13th term for first series is = a + 12d = 1292
13th terms for second series is = a + 12d = 2312
Ratio = 129231
a. 129231
b. 12
c. 2315
d. None of the above
Answer: a
Explanation:
Formula for sum of n terms in AP = Sn = n2(2a + (n – 1)d ]
5n + 4 ? 5(n – 1) + 9 ? [2(92)+(n?1)5]
Common difference (d) = 5, First term (a) = 92
Similarly
Second series given 9n + 6 ? 9(n – 1) + 15 ? [2(152)+(n?1)9]
Common difference (d) = 9, First term (a) = 152
So
13th term for first series is = a + 12d = 1292
13th terms for second series is = a + 12d = 2312
Ratio = 129231
6. A team P of 20 engineers can complete work or task in 32 days. Another team Q of 16 engineers can complete same task in 30 days.Then the ratio of working capacity of 1 member of P to the 1 member of Q is
a. 3 : 2
b. 4 : 3
c. 2 : 5
d. 3 : 5
Answer: b
Explanation:
Let the capacity of an engineer in P = x units, and in Q = y units.
Working capacity of P = x × 32 × 20
Working capacity of Q = y × 16 × 30
As the total work is same, we equate the above equations.
? x × 32 × 20 = y × 16 × 30
? xy=16×3032×20=34
a. 3 : 2
b. 4 : 3
c. 2 : 5
d. 3 : 5
Answer: b
Explanation:
Let the capacity of an engineer in P = x units, and in Q = y units.
Working capacity of P = x × 32 × 20
Working capacity of Q = y × 16 × 30
As the total work is same, we equate the above equations.
? x × 32 × 20 = y × 16 × 30
? xy=16×3032×20=34
7. Ravi’s salary was reduced by 25%. Percentage increase to be effected to bring salary to original level =
a. 20%
b. 25%
c. 33 1/3 %
d. None of the above
Answer: b
Explanation:
Let the Salary be 100.
Salary was reduced by 25%. So present salary = 75.
Percentage has to be increased in order to get Original level = 2575×100 = 33.33 %
a. 20%
b. 25%
c. 33 1/3 %
d. None of the above
Answer: b
Explanation:
Let the Salary be 100.
Salary was reduced by 25%. So present salary = 75.
Percentage has to be increased in order to get Original level = 2575×100 = 33.33 %
8. An ore contains 25% of an alloy that has 90% iron. Other than this, in remaining 75% of the ore ,there is no iron. How many kgs of the ore are needed to obtain 60 kg. of pure iron.?
a.250
b.275
c.300
d.166.66
Answer: d
Explanation:
Let us take 100x kgs of ore. Now it contains 25x kgs of alloy and it contains 90% (25x) kgs of iron.
90% (25x) = 60 kg ? x = 60×10090×125 = 83
So iron ore required = 100 × 83 = 266.66
a.250
b.275
c.300
d.166.66
Answer: d
Explanation:
Let us take 100x kgs of ore. Now it contains 25x kgs of alloy and it contains 90% (25x) kgs of iron.
90% (25x) = 60 kg ? x = 60×10090×125 = 83
So iron ore required = 100 × 83 = 266.66
9. Find the day of the week on 16th july, 1776.
a. Sunday
b. Monday
c. Tuesday
d. Wednesday
Answer: c
Explanation:
Split the year 1775 + 16th july 1776
Till 1600 years no odd days.
1601 to 1700 = 5 odd days
1701 to 1775 = 75 + 18 = 93 = 2 odd days. (75 years has 93 odd days (? 18 leap + 57 non leap years)
upto 15th july 1776 = 31 + 29 + 31 + 30 + 31 + 30 + 15 = 197 = 1 odd day.
Total odd days = 5 + 2 + 1 = 8 = 1 odd day.
So one day after Monday. That is Tuesday.
a. Sunday
b. Monday
c. Tuesday
d. Wednesday
Answer: c
Explanation:
Split the year 1775 + 16th july 1776
Till 1600 years no odd days.
1601 to 1700 = 5 odd days
1701 to 1775 = 75 + 18 = 93 = 2 odd days. (75 years has 93 odd days (? 18 leap + 57 non leap years)
upto 15th july 1776 = 31 + 29 + 31 + 30 + 31 + 30 + 15 = 197 = 1 odd day.
Total odd days = 5 + 2 + 1 = 8 = 1 odd day.
So one day after Monday. That is Tuesday.
10. The radius of a sphere is increased by 50%. The increase in surface area of the sphere is :
a. 100%
b. 125%
c. 150%
d. 200%
Answer: b
Explanation:
Take radius 100. Then surface area is 4 × ? × 100 × 100.
After increase radius by 50% the radius becomes100 + 50% of 100 = 150
Then new surface area is 4 × ? × 150 × 150
Then put the values into formula of percentage = 4?1502?4?10024?1002×100 = 125%
a. 100%
b. 125%
c. 150%
d. 200%
Answer: b
Explanation:
Take radius 100. Then surface area is 4 × ? × 100 × 100.
After increase radius by 50% the radius becomes100 + 50% of 100 = 150
Then new surface area is 4 × ? × 150 × 150
Then put the values into formula of percentage = 4?1502?4?10024?1002×100 = 125%
11. On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
A.Sunday
B.Thursday
C.Tuesday
D. Friday
Answer: d
Explanation:
8th Dec 2007 – 8th Dec 2006 = 52 weeks 1 day. So Dec 8th 2006 is behind one day = Friday
A.Sunday
B.Thursday
C.Tuesday
D. Friday
Answer: d
Explanation:
8th Dec 2007 – 8th Dec 2006 = 52 weeks 1 day. So Dec 8th 2006 is behind one day = Friday
12. Which one of the following option is the closest in the meaning to the word given below..
MITIGATE
a) Diminish
b) Divulge
c) Dedicate
d) Denote
Answer: a
Explanation:
Mitigate means to make something less severe. Divulge means reveal. Denote means indicate. Diminish means to make or to cause something to become less in size, importance etc.
MITIGATE
a) Diminish
b) Divulge
c) Dedicate
d) Denote
Answer: a
Explanation:
Mitigate means to make something less severe. Divulge means reveal. Denote means indicate. Diminish means to make or to cause something to become less in size, importance etc.
13. On increasing the price of T.V. sets by 30%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?
a. 4% increase
b. 4% decrease
c. 8% increase
d. 8% decrease
Answer: a
Explanation:
Let the price be = Rs.100, and number of units sold = 100
Then, sale value = Rs.(100 × 100) = Rs.10000
New sale value = Rs.(130 × 80) = Rs.10400
Increase% = 40010000 × 100 = 4%
a. 4% increase
b. 4% decrease
c. 8% increase
d. 8% decrease
Answer: a
Explanation:
Let the price be = Rs.100, and number of units sold = 100
Then, sale value = Rs.(100 × 100) = Rs.10000
New sale value = Rs.(130 × 80) = Rs.10400
Increase% = 40010000 × 100 = 4%
14. In an examination, 35% of total students failed in Hindi, 45% failed in English and 20% in both. The percentage of these who passed in both the subjects is :
a. 10%
b. 20%
c. 30%
d. 40%
Answer: d
Explanation:
Formula n(a?b) = n(a) + n(b) ? n(a?b)
Fail in Hindi or English = 35 + 45 – 20 = 60
Therefore students who passed = 100 – 60 = 40.
a. 10%
b. 20%
c. 30%
d. 40%
Answer: d
Explanation:
Formula n(a?b) = n(a) + n(b) ? n(a?b)
Fail in Hindi or English = 35 + 45 – 20 = 60
Therefore students who passed = 100 – 60 = 40.
15. Find the angle between the minute hand and hour hand of a click when the time is 7.20?
Answer: 100 degrees
Explanation:
Use formula ?=???30h?112m???
?=???30×7?112×20???=1000
Answer: 100 degrees
Explanation:
Use formula ?=???30h?112m???
?=???30×7?112×20???=1000
16. How will you measure height of building when you are at the top of the building? And if you have stone with you.
Answer:
Explanation:
Throw stone from top and note the time,t.
Find height using formula
s = u × t + 0.5 × g × t2
Where u = 0
Answer:
Explanation:
Throw stone from top and note the time,t.
Find height using formula
s = u × t + 0.5 × g × t2
Where u = 0
17. A contractor undertook to make 15 km of roadway in 40 weeks. In 10 weeks, 3 km was complete by 180 men working 8 hours a day. The men then agreed to work 1 hour a day overtime, And some boys were engaged to assist them, the work was finished in the stipulated time(40 weeks). How many boys were employed, if the work of 3 boys is equal to that of 2 men?
a) 70
b) 50
c) 60
d) 80
Answer: b
Explanation:
Let the capacity of man = 3 units, and boy = 2 units per hour.
Now total work = 3×180×8×7×10 = 3 km. – – – – – – – (1)
Let k boys were recruited. Now total work = (3×180+2×k) ×9×7×30 = 12km. – – – – – – (2)
By dividing 2nd equation by 1st,
? (540+2k)×9×7×303×180×8×7×10=4
? k = 50
a) 70
b) 50
c) 60
d) 80
Answer: b
Explanation:
Let the capacity of man = 3 units, and boy = 2 units per hour.
Now total work = 3×180×8×7×10 = 3 km. – – – – – – – (1)
Let k boys were recruited. Now total work = (3×180+2×k) ×9×7×30 = 12km. – – – – – – (2)
By dividing 2nd equation by 1st,
? (540+2k)×9×7×303×180×8×7×10=4
? k = 50
18. A can do a piece of work in 10 days, B in 15 days. They work for 5 days. The rest of work finished by C in 2 days.If they get Rs 1500 for the whole work, the daily wages of B and C are?
Answer:
Explanation:
Let the total work = 30 units.
Then capacity of A = 3 units, B = 2 units. Now they worked for 5 days. So they must have completed 25 units. Rest of the work 5 units done by C in 2 days. So C capacity = 5/2 = 2.5 units.
Given that toatal wages are Rs.1500 for 30 units. So for 1 unit of work they get Rs.50. Now B and C per day work = (2 + 2.5) = 4.5 units. So their daily wages = 4.5 × 50 = Rs.225
Answer:
Explanation:
Let the total work = 30 units.
Then capacity of A = 3 units, B = 2 units. Now they worked for 5 days. So they must have completed 25 units. Rest of the work 5 units done by C in 2 days. So C capacity = 5/2 = 2.5 units.
Given that toatal wages are Rs.1500 for 30 units. So for 1 unit of work they get Rs.50. Now B and C per day work = (2 + 2.5) = 4.5 units. So their daily wages = 4.5 × 50 = Rs.225
19. The average of ten numbers is 7 .If each number is multiplied by 12 , then the average of new set of numbers is :
a) 7
b) 19
c) 82
d) 84
Answer: d
Explanation:
If each number is multiplied by K, then the new average increases by K times. So new average = 84
a) 7
b) 19
c) 82
d) 84
Answer: d
Explanation:
If each number is multiplied by K, then the new average increases by K times. So new average = 84
20. In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 75 questions and secures 125 marks, the number of questions he attempts correctly, is :
a) 35
b) 40
c) 42
d) 46
Answer: B
Explanation:
Let the number of correct answers be x.
Then numbers of incorrect answers will be 75 – x
We get 4x – (75 – x)×1= 125
On solving the equation we get x= 40
a) 35
b) 40
c) 42
d) 46
Answer: B
Explanation:
Let the number of correct answers be x.
Then numbers of incorrect answers will be 75 – x
We get 4x – (75 – x)×1= 125
On solving the equation we get x= 40
21. A car moves at the speed of 80 km/hr. what is the speed of the car in metres per second?
A. 8 m/sec
B. 20 × 19 m/sec
C. 21 × 29 m/sec
D. 22 × 29 m/sec
Answer: D
Explanation:Formula
For convert km/hr into m/sec multiply the speed with 518
For convert m/sec into km/hr multiply the speed with 185
80 × 518 ? 22 × 29 m.sec.
A. 8 m/sec
B. 20 × 19 m/sec
C. 21 × 29 m/sec
D. 22 × 29 m/sec
Answer: D
Explanation:Formula
For convert km/hr into m/sec multiply the speed with 518
For convert m/sec into km/hr multiply the speed with 185
80 × 518 ? 22 × 29 m.sec.
22. 3 men can complete a piece of work in 6 days. Two days after they started the work, 3 more men joined them. How many days will they take to complete the remaining work?
Answer: 2 days
Explanation:
3 man 1 day work = 16
3 man 2 days work = 26
Remaining work = (1 – 26 ) = 2/3 parts.
6 man together perform the work in 1 day is = 16 + 16 = 26 parts
26 parts completed in 1 day
23 parts will b completed in 2 days
Answer: 2 days
Explanation:
3 man 1 day work = 16
3 man 2 days work = 26
Remaining work = (1 – 26 ) = 2/3 parts.
6 man together perform the work in 1 day is = 16 + 16 = 26 parts
26 parts completed in 1 day
23 parts will b completed in 2 days
23. A single discount % equal to three successive discounts of 30%, 20% and 10%.
A. 49.6%
B. 50.4%
C. 40%
D. 60%
E. None of these
Answer: a
Explanation:
Let the initial price be 100.
30% discount on 100 is 30
(100 – 30) = 70
20% discount on the 70 is 14
(70 – 14) = 56
10%discount on the 56 is 5.6
So the answer is 30 + 14 + 5.6 = 49.6
A. 49.6%
B. 50.4%
C. 40%
D. 60%
E. None of these
Answer: a
Explanation:
Let the initial price be 100.
30% discount on 100 is 30
(100 – 30) = 70
20% discount on the 70 is 14
(70 – 14) = 56
10%discount on the 56 is 5.6
So the answer is 30 + 14 + 5.6 = 49.6
24. If “PROMPT” is coded as QSPLOS ,then “PLAYER” should be
(a) QMBZFS
(b) QWMFDW
(c) QUREXM
(d) URESTI
Answer: QMBZFS
Explanation:
1st 3 letters are denoted by its next alphabet and the next 3 letters are denoted by its previous alphabets.
(a) QMBZFS
(b) QWMFDW
(c) QUREXM
(d) URESTI
Answer: QMBZFS
Explanation:
1st 3 letters are denoted by its next alphabet and the next 3 letters are denoted by its previous alphabets.
25. In a certain school, 20% of the students are below 8 yrs of age. The number of students above 8 yrs of age is (2/3) of the number of students of 8 years age which is 96. What is the total number of students in the school?
Answer: 200
Explanation:
Let total students be x.
? 0.2x + 23 × 96 + 96 = x
? x = 200
Answer: 200
Explanation:
Let total students be x.
? 0.2x + 23 × 96 + 96 = x
? x = 200
- Mr.P and Mr.Q can build a wall in 10 days; Mr.Q & Mr.R can take 14 days to build the same wall; and Mr.P and Mr.R can do it in 8 days. Who among them will take more time when they work alone?
a. p
b. q
c. r
d. data inadequate
Answer: b - Each week the forensics teams at Roslyn High School and Manchester High School debate each other. Each team has several members, and each week three are selected to debate. Whenever Aviva debates for Roslyn, Roslyn wins; and whenever Zachary debates for Roslyn, Roslyn wins. Whenever Josh debates for Roslyn, Manchester wins.
If one week Roslyn lost to Manchester, which of the following must be true?
(a) Josh debated for Roslyn.
(b) Either Aviva or Zachary debated for Roslyn.
(c) Neither Aviva nor Zachary debated for Roslyn.
(d) Josh and either Aviva or Zachary debated for Roslyn.
Answer: A - In a class of boys and girls Vikas’s rank is 9th and Tanvi’s rank is 17th . Vikas’s rank among the boys in that class is 4th from the top and 18th from the bottom and Tanvi’s rank among the girls is 8th from top and 21st from bottom. In the order of rank, how many girls are there between Tanvi and Vikas?
A) 1
B) 2
C) 5
D) 3
Answer: b - Two Equal Amounts of Money are lent out at 6% and 5 % simple Interest respectively at the same time. The former is recovered two years earlier than the latter and the amount so recovered in each case is Rs.2800. Determine the amount that is lent out?
A) 1950
B) 1500
C) 1800
D) 1375 - A starts business with Rs.3500 and after 5 months, B joins with A as his partner. After a year, the profit is divided in the ratio 2 : 3. What is B’s contribution in the Capital ?
Answer: 9000 - Rajan and Rakesh started a business and invested Rs.20000 and Rs.25000 respectively. After 4 months Rakesh left and Mukesh joined by investing Rs.15000. At the end of the year there was a profit of Rs.4600. What is the share of Mukesh?
A). Rs.1500
B). Rs.1400
C). Rs.1300
D). Rs.1200
Answer: d - Plastic strap are wound around large cardboard boxes to reinforce them during shipping. Suppose the end of the strap must overlap 7/16 inch to fasten. How long is the plastic strap around the box of dimensions 28 5/16 inch × 24 9/16 inch
A). 106 3/16
B). 96 3/16
C). 105 3/16
D). 107 3/16
Answer: a - In a game each person is dealt three cards from a deck of 52 cards and a player is said to have a winning deck if & only if he or she has a king, queen & a jack each , irrespective of the color of the sign. What is the total possible number of winning decks for this game?
(a)1
(b)4
(c)16
(d)64
(e)128
Answer: d - In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is :
a. 5
b. 7
c. 10
d. 12
Answer: b - A is 6 times as fast as B and takes 100 days less to complete a work than B. Find the total number of days taken by A and B to complete the work.
Answer: 120/7 days - If six persons sit around a table, the probability that some specified three of them are always together is
a)1/20
b)3/10
c)1/5
d)4/5
Answer: b - Out of four numbers ,the average of first three is 16 and that of the last three is 15 .If the last number is 18,the first number is :
A) 20
B) 21
C) 23
D) 25
Answer: b - Mr. X has to build a wall 1000 meters long in 50 days. He employs 56 men but at the end of 27 days finds that only 448 meters are built. How many more men must be employed so that the work may be finished in time?
a)58
b)81
c)38
d)25
Answer: d - In a race you drove 1st lap with 40 kmph and in the second lap at what speed you must drive so that your average speed must be 80 kmph.
Answer: Infinity - A and B working separately can do a piece of work in 6 and 9 days respectively; they work on alternate days starting with A on the first day. In how many days will the work be done?
Answer: 7 - In a certain office, 72% of the workers prefer tea and 44% prefer coffee. If each of them prefers tea or coffee and 40 like both, the total number of workers in the office is :
a. 200
b. 240
c. 250
d. 320
Answer: c - P & Q can draw a picture in 144 hours; Q & R can draw a same picture in 240 hours; P & R can finish it in 180 hours. What will be the time taken by P alone to draw the picture?
a) 280 hours
b) 240 hours
c) 200 hours
d) 300 hours
Answer: b - A 10 Liter mixture of milk and water contains 30 percent water. Two liters of this mixture is taken away. How many liters of water should now be added so that the amount of milk in the mixture is double that of water?
(a) 1.4
(b) 0.8
(c) 0.4
(d) 0.7
Answer: c - A frog can climb up a well at 3 ft per min but due to slipperiness of the well, frog slips down 2 ft before it starts climbing the next minute. If the depth of the well is 57 ft, how much time will the frog take to reach the top?
Answer: 55 min - A rectangle has twice the area of a square. The length of the rectangle is 14 cm greater than that side of the square whereas breadth is equal to side of the square. Find the perimeter of the square?
(a) 42 cm
(b) 14 cm
(c) 56 cm
(d) 28 cm
Answer: c - A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 20 km in 10 hours. How much time he would have saved if the direction of tide has not changed?
(a) 5 hrs
(b) 4 hrs
(c) 12 hrs
(d) 6 hrs
Answer: d
22.If half of 5 were 3, that would one-third of 10 be
(a) 5
(b) 4
(c) 3
(d) 2
Answer: b
(a) 5
(b) 4
(c) 3
(d) 2
Answer: b
- A butler is promised Rs. 100 and a cloak as his wages for a year. After 7 months he leaves this service, and receives the cloak and Rs.20 as his due. How much is the cloak worth?
(a) 76
(b) 84
(c) 92
(d) 68
Answer: c - A worm is at the bottom of a forty foot hole. It can crawl upwards at the rate of four feet in one day, but at night, it slips back three feet. At this rate, how long will it take the worm to crawl out of the hole?
(a) 29 days
(b) 37 days
(c) 35 days
(d) 39 days
Answer: c - Sohan purchased a horse for Rs.2000 and sold it to Mohan at a loss of 10 percent. Mohan sold it to Sham at a loss of 10 percent while sham sold it to Gopi at a gain of 10 percent. The amount Gopi paid for it would be
Answer: 1782 - On a map the distance between two mountains is 312 inches. The actual distance between the mountains is 136 km. Ram is camped at a location that on the map is 34 inch from the base of the mountain. How many km is he from the base of the mountain?
Answer: 14.82 km - Sixteen men complete a work in 24 days while 48 children can do it in 16 days. Twelve men started the work, after 14 days 12 children joined them. In how Many days will all of them together complete the remaining work?
Answer: 12 days - A father’s age was 5 times his son’s age 5 years ago and will be 3 times son’s age after 2 years, the ratio of their present ages is equal to:
a) 3:7
b) 5:11
c) 10:3
d) 10:7
Answer: c - 29. At a reception, one-third of the guests departed at a certain time. Later two-fifths of the guests departed. Even later two-thirds of the remaining guests departed. If six people were left, how many were originally present at the party?
- 30. Ratio between 2 numbers is 5 : 7 and their product is 560.what is the difference between 2 numbers?
